#include <string>
#include <vector>
#include <iostream>
#include <algorithm>
using namespace std;
const int mod = 1000000007;
typedef long long ll;
ll calc(ll x) {
	ll ret = 0;
	for (int i = 0; i < 60; i++) {
		ll cnt = (x >> i) - (x >> (i + 1));
		int d = to_string((i + 1) * (i + 1)).size();
		ret += d * cnt;
	}
	return ret;
}
vector<ll> solve(ll x) {
	ll l = 0, r = 1LL << 60;
	while (r - l > 1) {
		ll m = (l + r) >> 1;
		if (calc(m) <= x) l = m;
		else r = m;
	}
	vector<ll> v(10);
	for (int i = 0; i < 60; i++) {
		ll c = (l >> i) - (l >> (i + 1));
		int b = (i + 1) * (i + 1);
		while (b > 0) {
			v[b % 10] += c;
			b /= 10;
		}
	}
	ll pos = calc(l);
	int c = 1; l++;
	while (!(l & 1)) l >>= 1, c++;
	string t = to_string(c * c);
	for (int i = 0; i < x - pos; i++) v[t[i] - 48]++;
	return v;
}
int modpow(int a, ll b) {
	ll ret = 1;
	while (b) {
		if (b & 1) ret = 1LL * ret * a % mod;
		a = 1LL * a * a % mod;
		b >>= 1;
	}
	return ret;
}
int z[] = { 10, 1, 2, 3, 4, 5, 6, 7, 8, 9 };
ll K, L, R;
int main() {
	cin >> K >> L >> R; L--; K = min(K, 61LL);
	ll s = (1LL << K) - 1; s += s >> 9;
	if (R > s) cout << -1 << endl;
	else {
		vector<ll> r1 = solve(R), r2 = solve(L);
		long long sum = 0; int prod = 1;
		for (int i = 0; i < 10; i++) {
			sum += 1LL * z[i] * (r1[i] - r2[i]);
			prod = 1LL * prod * modpow(z[i], r1[i] - r2[i]) % mod;
		}
		cout << sum << ' ' << prod << endl;
	}
	return 0;
}