#include "bits/stdc++.h" using namespace std; #define FOR(i,j,k) for(int (i)=(j);(i)<(int)(k);++(i)) #define rep(i,j) FOR(i,0,j) #define each(x,y) for(auto &(x):(y)) #define mp make_pair #define mt make_tuple #define all(x) (x).begin(),(x).end() #define debug(x) cout<<#x<<": "<<(x)< pii; typedef vector vi; typedef vector vll; template class ModInt { public: ModInt() :value(0) {} ModInt(long long val) :value((int)(val<0 ? MOD + val%MOD : val%MOD)) { } ModInt& operator+=(ModInt that) { value = value + that.value; if (value >= MOD)value -= MOD; return *this; } ModInt& operator-=(ModInt that) { value -= that.value; if (value<0)value += MOD; return *this; } ModInt& operator*=(ModInt that) { value = (int)((long long)value * that.value % MOD); return *this; } ModInt &operator/=(ModInt that) { return *this *= that.inverse(); } ModInt operator+(ModInt that) const { return ModInt(*this) += that; } ModInt operator-(ModInt that) const { return ModInt(*this) -= that; } ModInt operator*(ModInt that) const { return ModInt(*this) *= that; } ModInt operator/(ModInt that) const { return ModInt(*this) /= that; } ModInt pow(long long k) const { if (value == 0)return 0; ModInt n = *this, res = 1; while (k) { if (k & 1)res *= n; n *= n; k >>= 1; } return res; } ModInt inverse() const { long long a = value, b = MOD, u = 1, v = 0; while (b) { long long t = a / b; a -= t * b; swap(a, b); u -= t * v; swap(u, v); } return ModInt(u); } int toi() const { return value; } private: int value; }; typedef ModInt<1000000007> mint; ostream& operator<<(ostream& os, const mint& x) { os << x.toi(); return os; } int gx, gy, K, use[5], N[5], dx[5], dy[5], sm; mint ans, fact[100]; void dfs(int x, int y, int k) { if (k == K) { if (x == gx&&y == gy) { mint z = fact[sm]; rep(i, K)z /= fact[use[i]]; ans += z; } return; } rep(i, N[k]+1) { use[k] = i; dfs(x + dx[k] * i, y + dy[k] * i, k + 1); sm++; } sm -= N[k] + 1; } int main(){ ios::sync_with_stdio(false); cin.tie(0); fact[0] = 1; rep(i, 99)fact[i + 1] = fact[i] * (i + 1); cin >> gx >> gy >> K; rep(i, K) { cin >> dx[i] >> dy[i] >> N[i]; } dfs(0, 0, 0); cout << ans << endl; }