#include "bits/stdc++.h"
using namespace std;

typedef long long ll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;

#define FOR(i, s, e) for (ll(i) = (s); (i) < (e); (i)++)
#define FORR(i, s, e) for (ll(i) = (s); (i) > (e); (i)--)
#define debug(x) cout << #x << ": " << x << endl
#define mp make_pair
#define pb push_back
const ll MOD = 1000000007;
const int INF = 1e9;
const ll LINF = 1e16;
const double PI = acos(-1.0);
int dx[8] = { 0, 0, 1, -1, 1, 1, -1, -1 };
int dy[8] = { 1, -1, 0, 0, 1, -1, 1, -1 };

/* -----  xtimex  Problem:  / Link:   ----- */
/* ------問題------



-----問題ここまで----- */
/* -----解説等-----



----解説ここまで---- */

ll N, target;
ll a[50];
bool memo[51][100110];
ll ans = 0LL;
string s = "";
void f(int i, ll sum) {
	//cout << s << endl;
	if (sum > target)return;
	if (i == N&&sum == target) {
		cout << s << endl;
		exit(0);
	}
	if (i >= N )return;
	if (memo[i][sum])return;
	memo[i][sum] = 1;
	s += '+';
	f(i + 1, sum + a[i]);
	s.erase(s.size() - 1);
	s += '*';
	f(i + 1, sum * a[i]);
	s.erase(s.size() - 1);

	return;
}

int main() {
	cin.tie(0);
	ios_base::sync_with_stdio(false);

	FOR(i, 0, 50)FOR(j, 0, 100011) memo[i][j] = 0;

	cin >> N >> target;
	FOR(i, 0, N)cin >> a[i];
	f(1, a[0]);

	return 0;
}