N = int(input())
shift =  N - bin(2 * N)[2:].count("1")  #(2N)!の偶数項

z = 1000000007

memo = {i:1 for i in range(3, 2 * N + 1, 2)}
r = 2 * N + 1
while r != 1:
    r = int(r / 2)
    for i in range(3, r + 1, 2):
        memo[i] += 1
odds = 1
for i in memo:
    odds = odds * i ** memo[i]

ans = (odds << shift) % z
print(ans)