N = int(input())
shift =  N - bin(2 * N)[2:].count("1")  #(2N)!の偶数項
mod = 1000000007
odds = 1
for i in range(3, 2 * N + 1, 2):
    odds = odds * i
    if odds > mod:
        odds -= mod

ans = (odds << shift) % mod
print(ans)