# lru_cache によるメモ化再帰

import functools


mod = 10**9+7

memo = [[0] * 222 for _ in range(222)]

@functools.lru_cache(maxsize=None)
def calc(a, b):
    if a == 1 or b == 1:
        return 1

    if memo[a][b] != 0:
        return memo[a][b]

    memo[a][b] = (calc(a - 1, b) + calc(a, b - 1)) % mod

    return memo[a][b]


def solve():
    a, b, c = map(int, input().split())

    ans = 0

    ans += calc(a, b + c + 1)
    ans += calc(b, c + a + 1)
    ans += calc(c, a + b + 1)

    if ans > mod: ans %= mod

    for i in range(a):
        for j in range(b):
            for k in range(c):
                x = calc(i+1, c-k)

                x *= calc(j+1, a-i)
                if x > mod: x %= mod

                x *= calc(k+1, b-j)
                if x > mod: x %= mod

                ans += x
                if ans > mod: ans %= mod

    return ans


t = int(input())
for _ in range(t):
    print(solve())