#include #define rep(i, n)for(int i=0;i<(n);i++) using namespace std; typedef long long int64; int64 dp[100001][2]; int64 dp2[100001]; int64 rec2(int idx, const int mod) { if(idx <= 0) return (1); if(idx % 2 == 1) return (rec2(idx - 1, mod) * 10 % mod); if(~dp2[idx]) return (dp2[idx]); return (dp2[idx] = rec2(idx - 2, mod) * 10 % mod); } int64 solve(string a, int MOD) { memset(dp2, -1, sizeof(dp2)); int64 ret = 0; for(int i = 0; i < a.size() - 1; i++) { ret += rec2(i - 1, MOD) * 9; ret %= MOD; } memset(dp, 0, sizeof(dp)); dp[0][0] = 1; rep(i, a.size() / 2) rep(j, 2) { if(dp[i][j] == 0)continue; int g = (j ? 9 : a[i] - '0'); rep(l, g + 1)(dp[i + 1][j || l < g] += dp[i][j]) %= MOD; } return (ret); } int main() { string b; cin >> b; int MOD = 1e9; if(b.size() % 2 == 1) printf("%lld\n", (solve(b, MOD) + (dp[b.size() / 2][0] + dp[b.size() / 2][1] * 10)) % MOD); else printf("%lld\n", (solve(b, MOD) + dp[b.size() / 2][0] + dp[b.size() / 2][1] - 1 + MOD) % MOD); MOD = 1e9 + 7; if(b.size() % 2 == 1) printf("%lld\n", (solve(b, MOD) + (dp[b.size() / 2][0] + dp[b.size() / 2][1] * 10)) % MOD); else printf("%lld\n", (solve(b, MOD) + dp[b.size() / 2][0] + dp[b.size() / 2][1] - 1 + MOD) % MOD); }