MOD = 1000000007

n = gets.to_i

dp1 = Array.new(n+4,0)
dp2 = Array.new(n+4,0)
dp3 = Array.new(n+4,0)

dp1[1] = 1
dp2[2] = 1
dp3[3] = 1

1.upto(n-1){|i|
    dp1[i+1] = (dp1[i+1]+dp2[i]+dp3[i])%MOD
    dp2[i+2] = (dp2[i+2]+dp1[i]+dp3[i])%MOD
    dp3[i+3] = (dp3[i+3]+dp1[i]+dp2[i])%MOD
}

p (dp1[n]+dp2[n]+dp3[n])%MOD