#include <algorithm>
#include <cstdio>
#include <iostream>
#include <map>
#include <cmath>
#include <queue>
#include <set>
#include <sstream>
#include <stack>
#include <string>
#include <vector>
#include <stdlib.h>
#include <stdio.h>
#include <bitset>
using namespace std;
#define FOR(I,A,B) for(int I = (A); I < (B); ++I)
typedef long long ll;

double d(double x1, double y1, double x2, double y2) {
  return sqrt((x1-x2)*(x1-x2)+(y1-y2)*(y1-y2));
}
int main(){
  double x[3], y[3];
  FOR (i,0,3) {
    cin >> x[i] >> y[i];
  }
  FOR(i,0,3) {
    if(d(x[i%3], y[i%3], x[(i+1)%3], y[(i+1)%3]) == d(x[i%3], y[i%3], x[(i+2)%3], y[(i+2)%3])) {
      if(sqrt(2.0) * d(x[i%3],y[i%3],x[(i+1)%3],y[(i+1)%3]) == d(x[(i+2)%3],y[(i+2)%3],x[(i+1)%3],y[(i+1)%3])) {
        // 正方形になる点を探す
        for (double xx = -200; xx <= 200; xx++) {
          for (double yy = -200; yy <= 200; yy++) {
            if(d(xx, yy, x[(i+1)%3], y[(i+1)%3]) == d(xx, yy, x[(i+2)%3], y[(i+2)%3])) {
              if(sqrt(2.0) * d(xx,yy,x[(i+1)%3],y[(i+1)%3]) == d(x[(i+2)%3],y[(i+2)%3],x[(i+1)%3],y[(i+1)%3])) {
                if(xx == x[i%3] && yy == y[i%3]) continue;
                cout << int(xx) << " " << int(yy) << endl;
                return 0;
              }
            }
          }
        }
      }
    }
  }
  cout << -1 << endl;
  return 0;
}