#pragma GCC optimize ("O3") #pragma GCC target ("avx") #include "bits/stdc++.h" // define macro "/D__MAI" using namespace std; typedef long long int ll; #define debugv(v) printf("L%d %s => ",__LINE__,#v);for(auto e:v){cout< ",__LINE__,#m);for(int x=0;x<(w);x++){cout<<(m)[x]<<" ";}cout< ostream& operator <<(ostream &o, const pair p) { o << "(" << p.first << ":" << p.second << ")"; return o; } #define TIME chrono::system_clock::now() #define MILLISEC(t) (chrono::duration_cast(t).count()) namespace { std::chrono::system_clock::time_point ttt; void tic() { ttt = TIME; } void toc() { fprintf(stderr, "TIME : %lldms\n", MILLISEC(TIME - ttt)); } std::chrono::system_clock::time_point tle = TIME; #ifdef __MAI void safe_tle(int msec) { assert(MILLISEC(TIME - tle) < msec); } #else #define safe_tle(k) ; #endif } #ifdef __MAI #define getchar_unlocked getchar #define putchar_unlocked putchar #endif #ifdef __VSCC #define getchar_unlocked _getchar_nolock #define putchar_unlocked _putchar_nolock #endif namespace { #define isvisiablechar(c) (0x21<=(c)&&(c)<=0x7E) class MaiScanner { public: template void input_integer(T& var) { var = 0; T sign = 1; int cc = getchar_unlocked(); for (; cc<'0' || '9'>(int& var) { input_integer(var); return *this; } inline MaiScanner& operator>>(long long& var) { input_integer(var); return *this; } inline MaiScanner& operator>>(string& var) { int cc = getchar_unlocked(); for (; !isvisiablechar(cc); cc = getchar_unlocked()); for (; isvisiablechar(cc); cc = getchar_unlocked()) var.push_back(cc); } }; } MaiScanner scanner; int rr, bb; int dfs(const string&); unordered_map memo[32]; int pick(string state,int idx) { state.erase(idx, 1); int size = state.size(); if (memo[size].count(state)) return memo[size][state]; return memo[size][state] = dfs(state); } int dfs(const string& state) { int best = -1; { int i = 0; int last_r = -1; int last_b = -1; for (; i < state.size() - 1;++i) { int lookup_r = min(i + rr, (int)state.size() - 1); int lookup_b = min(i + bb, (int)state.size() - 1); // Rのforbiddenを解消するために,Bを削除することもできる. // この解答ではそれを考慮しないため,落ちる. if (state[i] == 'R' && state[lookup_r] == 'R') { if (last_r != i) best = max(best, pick(state, i)); best = max(best, pick(state, lookup_r)); last_r = lookup_r; } if (state[i] == 'B' && state[lookup_b] == 'B') { if (last_b != i) best = max(best, pick(state, i)); best = max(best, pick(state, lookup_b)); last_b = lookup_b; } } } if (best == -1) { return state.size() - 1; } else { return best; } } int main() { cin >> rr >> bb; string str; cin >> str; str.push_back('$'); cout << dfs(str) << endl; return 0; }