#include <iostream>
using namespace std;
long long n, a[1000009];
long long solve(long long x) {
	if (x <= 1000000) return a[x];
	return solve(x / 3) + solve(x / 5);
}
int main() {
	a[0] = 1;
	for (int i = 1; i <= 1000000; i++) a[i] = a[i / 3] + a[i / 5];
	cin >> n;
	cout << solve(n) << endl;
	return 0;
}