#include <bits/stdc++.h>
#define FOR(i,a,b) for (int i=(a);i<(b);i++)
#define FORR(i,a,b) for (int i=(a);i>=(b);i--)
#define pb push_back
#define pcnt __builtin_popcount
#define show(x) cout<<#x<<" = "<<x<<endl;
#define maxs(x,y) x = max(x,y)
#define mins(x,y) x = min(x,y)
#define fi first
#define se second
#define rng(a) a.begin(),a.end()
#define each(it,c) for(__typeof((c).begin()) it=(c).begin();it!=(c).end();it++)
#define sz(x) (int)(x).size()
#define mp make_pair

using namespace std;
typedef long long ll;
typedef pair<int,int> pii;
typedef vector<int> vi;
typedef vector<vi> vvi;
typedef vector<pii> vpii;
typedef set<int> si;
typedef pair<ll,ll> pll;
typedef vector<ll> vl;
typedef vector<vl> vvl;
typedef vector<pll> vpll;
typedef set<ll> sl;
template<typename T>string join(vector<T>&v)
{stringstream s;FOR(i,0,sz(v))s<<' '<<v[i];return s.str().substr(1);}
ll gcd(ll a,ll b){if(a>b)swap(a,b);for(;a>0;b%=a,swap(a,b));return b;}
int modpow(ll a,ll n,int m){if(a==0)return a;ll p=1;for(;n>0;n/=2,a=a*a%m)if(n&1)p=p*a%m;return(int)p;}
void dout(double d){printf("%.12f\n",d);}

const int iinf = 1e9;
const ll linf = 1e18;
const int mod = 1e9+7;
const double pi = acos(-1);
const double eps = 1e-10;
ll n, k;
map<int, vi> M;
vpii v;

struct Prime{
  vl pl;
  bool is_prime(ll a){
    if(a < 2)return false;
    each(itr, pl){
      if(*itr * *itr > a)return true;
      if(a%*itr == 0)return false;
    }
    return true;
  }
  void init(int a){
    pl.resize(0);
    pl.pb(2);
    pl.pb(3);
    int i = 5;
    while(i <= a){
      if(is_prime(i)) pl.pb(i);
      i += 2;
      if(is_prime(i)) pl.pb(i);
      i += 4;
    }
  }
  void prime_division(ll a, vpii&v){ // vに素因数分解の結果が入る
    v.resize(0);
    for(vl::iterator itr = pl.begin(); *itr * *itr <= a; itr++){
      if(a%*itr == 0){
        ll c = 0;
        while((a%*itr) == 0){
          a /= *itr;
          c++;
        }
        v.pb(pii(*itr, c));
      }
    }
    if(a > 1)v.pb(pii(a, 1));
  }
};
Prime p;

main(){
  cin.tie(0);
  ios::sync_with_stdio(false);
  p.init(40000);
  cin >> n >> k;
  FOR(i, 0, n){
    ll a;
    cin >> a;
    p.prime_division(a, v);
    each(itr, v) M[itr->fi].pb(itr->se);
  }
  ll ans = 1;
  each(itr, M){
    ll s = 0, b = sz(itr->se);
    sort(rng(itr->se));
    FOR(i, 0, min(k, b)) s += itr->se[b-i-1];
    ans = ans * modpow(itr->fi, s, mod) % mod;
  }
  cout << ans << endl;
  return 0;
}