#include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include #define ll long long #define fi first #define se second using namespace std; const ll MOD=(ll)1e9+7; string a,b,p; ll dp[200010][2][2][3]; ll dp1[10][2][2][3][800]; //ll dp[200010][2][2][3][8][2][2]; inline ll solve(string s,string p){ int n=(int)s.length(); int m=(int)p.length(); int h=stoi(p); m+=2; if(n-m<=0)return -114; for(int i=0;i<200010;i++) for(int j=0;j<2;j++) for(int k=0;k<2;k++) for(int l=0;l<3;l++) dp[i][j][k][l]=0; dp[0][0][0][0]=1; for(int i=0;i=0;i--){ int now=s[i]-'0'; if(now-1<0){ s[i]='9'; }else{ s[i]=char('0'+now-1); break; } } for(int i=0;i<(int)s.length();i++){ if(s=="0")break; if(s[i]=='0')s=s.substr(1,s.length()-1); else break; } return s; } int main(){ ios::sync_with_stdio(false); cin.tie(0); cout.precision(10); cout<>a>>b>>p; string newa=min1(a); ll ansb=solve(b,p); if(ansb==-114)ansb=solve2(b,stoi(p)); ll ansa=solve(newa,p); if(ansa==-114)ansa=solve2(newa,stoi(p)); //cout<