#include using namespace std; using ll = long long; #define rep(i,n) for(int (i)=0;(i)<(int)(n);++(i)) #define all(x) (x).begin(),(x).end() #define pb push_back #define fi first #define se second #define dbg(x) cout<<#x" = "<<((x))< ostream& operator<<(ostream& o, const pair &p){o<<"("< ostream& operator<<(ostream& o, const vector &v){o<<"[";for(T t:v){o<=0) return dp1[from][to][step]; if(step==0) { if(from==to) return 0; return -INF; } ll ret = 0; rep(i,m) ret = max(ret, f(i,to,step-1)+a[from][i]); return dp1[from][to][step] = ret; } ll dp2[30][62]; ll g(int s, int elim) { if(dp2[s][elim]>=0) return dp2[s][elim]; ll rem = n-elim; if(rem<0) return -INF; ll ret = 0; for(int i=1; i<=30; ++i) { if(rem%i==0) ret = max(ret,(rem/i)*f(s,s,i)); } return dp2[s][elim] = ret; } int main() { cin >>n >>m; --n; rep(i,m)rep(j,m) cin >>a[i][j]; memset(dp1,-1,sizeof(dp1)); memset(dp2,-1,sizeof(dp2)); ll ans = 0; rep(i,m)rep(j,m)rep(k,m)rep(ii,31)rep(jj,31) { ans = max(ans, f(i,k,ii) + g(k,ii+jj) + f(k,j,jj)); } cout << ans << endl; return 0; }