#define _USE_MATH_DEFINES
#include "bits/stdc++.h"
using namespace std;
#define FOR(i,j,k) for(int (i)=(j);(i)<(int)(k);++(i))
#define rep(i,j) FOR(i,0,j)
#define each(x,y) for(auto &(x):(y))
#define mp make_pair
#define mt make_tuple
#define all(x) (x).begin(),(x).end()
#define debug(x) cout<<#x<<": "<<(x)<<endl
#define smax(x,y) (x)=max((x),(y))
#define smin(x,y) (x)=min((x),(y))
#define MEM(x,y) memset((x),(y),sizeof (x))
#define sz(x) (int)(x).size()
#define pb push_back
typedef long long ll;
typedef pair<int, int> pii;
typedef vector<int> vi;
typedef vector<ll> vll;

/*
Legendre's formula

nを自然数、pを素数とするとき
p^x | n!
を満たす最大の非負整数xを返す。
時間
O(log(n))

参考
https://en.wikipedia.org/wiki/Legendre%27s_formula
*/
long long LegendreFormula(long long n, long long p) {
    long long res = 0, d = p, a;
    while ((a = n / d) != 0) {
        res += a;
        d *= p;
    }
    return res;
}

/*
スターリングの近似
log(n!)の近似
https://ja.wikipedia.org/wiki/%E3%82%B9%E3%82%BF%E3%83%BC%E3%83%AA%E3%83%B3%E3%82%B0%E3%81%AE%E8%BF%91%E4%BC%BC
*/
double stirlingsApproximation(long long n) {
    return n * log(n) - n + 0.5*log(2 * M_PI*n) + 1.0 / (12.0*n);
}

int main(){
    ios::sync_with_stdio(false);
    cin.tie(0);
    cout << fixed << setprecision(10);
    ll n, m, p;
    cin >> n >> m;
    ll M = m;
    double x = stirlingsApproximation(n);

    ll divnum = LLONG_MAX;
    auto f = [&](ll p, int cnt) {
        smin(divnum, LegendreFormula(n, p) / cnt);
    };
    for (p = 2; p*p <= m; ++p) {
        if (m%p == 0) {
            int cnt = 0;
            while (m%p == 0)m /= p, ++cnt;
            f(p, cnt);
        }
    }

    if (m != 1) {
        f(m, 1);
    }
    x -= divnum * log(M);
    double x10 = x / log(10.0);
    ll pw = (ll)x10;
    x10 -= pw;
    x = x10 * log(10);
    cout << exp(x) << 'e' << pw << endl;
}