#include "bits/stdc++.h"
using namespace std;
using LL = long long;

#define ALL(a)  begin((a)),end((a))
#define SZ(a) int((a).size())
#define FOR(i, s, e) for (int(i) = (s); (i) < (e); (i)++)

/* -----  2017/11/18  Problem: yukicoder362 / Link: __CONTEST_URL__  ----- */



LL dp[20][10][10][3][2];
LL f(string &s, int i, int befbef = 0, int bef = 0, int up = 0, int less = 0) {
	if (i == -1) {
		return 1;
	}
	if (less == 1 && dp[i][befbef][bef][up][less] != -1)return dp[i][befbef][bef][up][less];
	LL res = 0;
	int num = s[i] - '0';
	int Max = less ? 9 : num;
	FOR(nx, 0, Max + 1) {
		if (up == 0) {// 0,5,?
			if (bef == 0)res += f(s, i - 1, bef, nx, (0), less || (nx < Max));
			else if (nx > bef)res += f(s, i - 1, bef, nx, (1), less || (nx < Max));
			else if (nx < bef)res += f(s, i - 1, bef, nx, (2), less || (nx < Max));
		}
		else if (up == 1) {// 1,4,?
			if (nx < bef&&befbef != nx)res += f(s, i - 1, bef, nx, (2), less || (nx < Max));
		}
		else if (up == 2) {
			if (nx > bef&&befbef != nx)res += f(s, i - 1, bef, nx, (1), less || (nx < Max));
		}
	}
	if (less == 1)return dp[i][befbef][bef][up][less] = res;
	else return res;
}

LL two(LL x) {
	string s = to_string(x);
	reverse(ALL(s));
	
	return f(s, SZ(s) - 1);
}

void solve(LL kado) {
	LL L = 0; LL R = 37294859064823 + 1;
	LL mid;
	FOR(i, 0, 60) {
		mid = (L + R) / 2;
		if (two(mid)-91 >= kado) {
			R = mid;
		}
		else L = mid;

	}
	printf("%lld\n", R);
}



int main() {

	fill(****dp, ****dp + 20 * 10 * 10 * 3 * 2, -1);
	int N;  scanf("%d", &N);
	FOR(i, 0, N) {
		LL a; scanf("%lld", &a);
		solve(a);
	}

	return 0;
}