#include #define rep(i, n) for (lli i = 0; i < (n); i++) #define rrep(i, n) for (lli i = (n)-1; i >= 0; i--) using namespace std; using lli = long long int; string s; lli mod = 1e9 + 7; int n; lli base[2] = {97, 103}; lli p[2] = {(lli)1e9 + 7, (lli)1e9 + 9}; lli dp[10005][10005] = {}; int hash_[10005][10005][2] = {}; void fill() { // hash [l,r) rep(i, n) { for (int j = i; j < n; j++) { rep(k, 2) hash_[i][j + 1][k] = int((lli)base[k] * (lli)hash_[i][j][k] + s[j]) % p[k]; } } } lli f(lli l, lli r) { lli ll = l, rr = r; if (l >= r) return 0; //cout << l << " " << r << endl; if (dp[l][r] != 0) return dp[l][r]; dp[l][r] = 1; rep(i, n) { if (ll >= rr) { break; } // s l..ll == s rr .. r bool flag = true; rep(k, 2) { flag &= (hash_[l][ll + 1][k] == hash_[rr - 1][r][k]); } if (flag) dp[l][r] += f(ll + 1, rr - 1); dp[l][r] %= mod; ll++, rr--; } return dp[l][r]; } int main() { cin >> s; n = s.size(); fill(); // cout << hash_[0][3][1] << endl; // cout << hash_[6][9][1] << endl; cout << f(0, n) << endl; }