#include <algorithm>
#include <bitset>
#include <cassert>
#include <cmath>
#include <complex>
#include <cstdint>
#include <cstdio>
#include <deque>
#include <functional>
#include <iomanip>
#include <iostream>
#include <limits>
#include <map>
#include <numeric>
#include <queue>
#include <set>
#include <sstream>
#include <stack>
#include <tuple>
#include <utility>
#include <vector>
using namespace std;

using ll = long long;

const ll MOD = 1000003;

struct R {
    ll n, k;
    R () {}
    R (ll n, ll k) : n(n), k(k) { }

    bool operator < (const R& o) const {
        bool r1 = (n + 1) * (o.n + 1 - o.k) == (o.n + 1) * (n + 1 - k);
        return r1 ? k < o.k : (n + 1) * (o.n + 1 - o.k) < (o.n + 1) * (n + 1 - k);
    }
};

ll modpow(ll a, int b) {
    if (b == 0) return 1LL;
    if (b == 1) return a;
    if (b % 2 == 1) return a * modpow(a, b-1);
    ll h = modpow(a, b/2);
    return h * h % MOD;
}

ll modinv(ll a) {
    return modpow(a, MOD-2);
}

int main() {
    cin.tie(0); ios::sync_with_stdio(false);
    ll s[26];
    string T; for (int j = 0; j < 26; ++j) {
        cin >> s[j];
    }
    cin >> T;

    int co[26];
    fill(co, co+26, 0);
    for (const char ch : T) {
        ++co[ch-'a'];
    }
    for (int j = 0; j < 26; ++j) {
        if (co[j] > s[j]) {
            cout << 0 << endl;
            return 0;
        }
    }

    vector<int> cu[26];
    char prev = T[0]; int count = 0;
    for (const char ch : T) {
        if (prev == ch) {
            ++count;
        } else {
            cu[prev-'a'].push_back(count);
            count = 1;
        }
        prev = ch;
    }
    cu[prev-'a'].push_back(count);

    ll ans = 1LL;
    for (int j = 0; j < 26; ++j) {
        priority_queue<R> pq;
        for (int v : cu[j]) {
            pq.emplace(v, v);
        }

        if (pq.empty()) continue;

        for (int k = 0; k < s[j] - co[j]; ++k) {
            R r = pq.top(); pq.pop();
            ans = ans * (r.n + 1) % MOD * modinv(r.n + 1 - r.k) % MOD;
            pq.emplace(r.n+1, r.k);
        }
    }
    cout << ans << endl;
    return 0;

}