#include using namespace std; using VI = vector; using VVI = vector; using PII = pair; using LL = long long; using VL = vector; using VVL = vector; using PLL = pair; using VS = vector; #define ALL(a) begin((a)),end((a)) #define RALL(a) (a).rbegin(), (a).rend() #define PB push_back #define EB emplace_back #define MP make_pair #define SZ(a) int((a).size()) #define SORT(c) sort(ALL((c))) #define RSORT(c) sort(RALL((c))) #define UNIQ(c) (c).erase(unique(ALL((c))), end((c))) #define FOR(i,a,b) for(int i=(a);i<(b);++i) #define REP(i,n) FOR(i,0,n) #define FF first #define SS second template istream& operator>>(istream& is, pair& p){ return is >> p.FF >> p.SS; } template ostream& operator<<(ostream& os, const pair& p){ return os << p.FF << " " << p.SS; } template void maxi(T& x, T y){ if(x < y) x = y; } template void mini(T& x, T y){ if(x > y) x = y; } const double EPS = 1e-10; const double PI = acos(-1.0); using LLL = __int128; const LLL MOD = 1e6+3; LLL powm(LLL a, LLL b){ return (b==0? 1: powm(a*a%MOD,b/2) * (b%2==1?a:1) % MOD); } LLL inv(LLL x){ return powm(x, MOD-2); } LLL solve(LLL rest, LLL sum, VL& vs){ if(rest == 0 || vs.empty()) return 1; LLL n = SZ(vs); if(rest > n*MOD) return 0; using FRAC = pair; // (first / second) auto lt = [](const FRAC& l, const FRAC& r){ return l.first * r.second < r.first * l.second; }; priority_queue,decltype(lt)> pq(lt); for(LL v: vs) pq.push(MP(v+1, 1)); rest -= sum; LLL res = 1; while(rest){ --rest; auto p = pq.top(); pq.pop(); if(p.FF >= MOD || res == 0) return 0; (res = res * p.first % MOD * inv(p.second)) %= MOD; pq.push(MP(p.first+1, p.second+1)); } return res; } int main(){ cin.tie(0); ios_base::sync_with_stdio(false); VL S(26); REP(i,26) cin >> S[i]; string T; cin >> T; VL sum(26); VVL vs(26); REP(i,SZ(T)){ int c = T[i] - 'a'; sum[c]++; if(!i || T[i] != T[i-1]) vs[c].PB(1); else vs[c].back()++; } REP(i,26) if(S[i] < sum[i]){ cout << 0 << endl; return 0; } LLL ans = 1; REP(c,26){ LLL res = solve(S[c], sum[c], vs[c]); (ans *= res) %= MOD; if(!ans) break; } cout << (LL)(ans) << endl; return 0; }