#include <iostream>
#include <string>
#include <math.h>
using namespace std;
typedef long long LL;
int main(int argc, char* argv[])
{
	string N;
	cin>>N;
	int i;
	int len=N.length()-1;
	LL m=0;
	for (i=len;i>=0;i--){
		int n=N[i]-'0';
		m+=n*(LL)(pow(4.0,len-i));
	}
	if (m%3==0 && m%5==0){
		cout<<"FizzBuzz"<<endl;
	}else if (m%3==0){
		cout<<"Fizz"<<endl;
	}else if (m%5==0){
		cout<<"Buzz"<<endl;
	}else{
		cout<<N<<endl;
	}
	return 0;
}