def calc(x)
    (1..100000).bsearch {|k| x < k*(k+1)/2 }-1
end

def bye(x)
    p x
    exit
end
    
n = gets.to_i

0.upto(4500) do |k|
    bye 1 if k*(k+1)/2 == n
end

1.upto(4500) do |k|
    rk = k*(k+1)/2
    k.upto(4500) do |l|
        rl = l*(l+1)/2
        bye 2 if rl + rk == n
    end
end
bye 3