#include <iostream>
#include <cmath>
using namespace std;
using ll = long long;
int main()
{
ll N;cin >>N;
const ll m = sqrt(2*N);
if(m*(m+1)/2 == N){
cout << "YES"<<endl;
cout << m << endl;
} else {
cout << "NO"<<endl;
}
return 0;
}