import heapq
#import re
#import bisect
#from collections import deque

n, v, ox, oy = (int(i) for i in input().split())
l = [[int(i) for i in input().split()] for i in range(n)]
cost = [[0xFFFFFFFF for i in range(n)] for j in range(n)]
direction = ((1, 0), (0, 1), (-1, 0), (0, -1))
def solve(x, y):
    h = []
    heapq.heappush(h, (x << 8) + y)
    inq = [[False for i in range(n)] for j in range(n)]
    for i in range(n):
        for j in range(n):
            cost[i][j] = 0xFFFFFFFF
    cost[y][x] = 0
    inq[y][x] = True
    while (h):
        vh = heapq.heappop(h)
        vx = (vh >> 8) & 0x00FF
        vy = vh & 0x00FF
        nowcost = cost[vy][vx]
        inq[vy][vx] = False
        for i in range(4):
            mx = vx + direction[i][0]
            my = vy + direction[i][1]
            if(mx < 0 or my < 0 or mx >= n or my >= n):
                continue
            newcost = nowcost + l[my][mx]
            if cost[my][mx] > newcost:
                cost[my][mx] = newcost                
                if inq[my][mx] == False:
                    inq[my][mx] = True
                    heapq.heappush(h, (mx << 8) + my)

solve(0, 0)
if cost[n - 1][n - 1] < v:
    print("YES")
else:
    if (ox > 0 and oy > 0):
        os = cost[oy - 1][ox - 1]
        if os < v:
            solve(ox - 1, oy - 1)
            if cost[n - 1][n - 1] < (v - os) * 2:
                print("YES")
            else:
                print("NO")
        else:
            print("NO")
    else:
        print("NO")