#include #include #include #include using namespace std; typedef long long ll; #define N (1<<24) #define M 100010 int m, n, mx, ax, my, ay, mod, mod2, mod3 = 1<<30; //ll x[M], y[M], z[N], a[M], b[M]; vector x, y, z, a, b; //bool prime[N]; vector prime; ll solve(ll a, ll b){ b *= a; return (a(m); z = vector(mod); prime = vector(mod); for(int i = 0; i < m; i++) scanf("%d", &x[i]); for(int i = 0; i < m; i++) scanf("%d", &y[i]); for(int i = 0; i < m; i++) z[x[i]] += y[i]; ll xx = x[m-1], yy = y[m-1]; for(int i = m; i < n; i++){ xx = (xx*mx+(ll)ax)&(mod-1); yy = (yy*my+(ll)ay)&(mod-1); z[xx] += yy; } for(int i = 2; i*i 0; j-=i){ z[j/i] += z[j]; } } for(int i = 0; i < m; i++) scanf("%d", &a[i]); for(int i = 0; i < m; i++) scanf("%d", &b[i]); ll res = 0; for(int i = 0; i < m; i++){ ll r = solve(a[i], b[i]); printf("%lld\n", r); (res+=r)&=mod3-1; } ll aa = a[m-1], bb = b[m-1]; for(int i = m; i < n; i++){ aa = ((aa*mx+(ll)ax+mod2-1)&(mod2-1))+1; bb = ((bb*my+(ll)ay+mod2-1)&(mod2-1))+1; (res+=solve(aa, bb))&=mod3-1; } printf("%lld\n", res); return 0; }