#include #include #include #include #include #include #include #include #include #include #include #include #include #define p(s) cout<<(s)<=n;i--) #define CK(n,a,b) ((a)<=(n)&&(n)<(b)) #define F first #define S second typedef long long ll; using namespace std; const ll inf = 1e10; int N, M; int a[100010]; bool C(int mid){//index int mn=1; int mx=N-1; int cnt=0; int X = a[0] + a[mid]; while(mx - mn>0){ if(mx == mid) { mx--;continue; } if(mn == mid){ mn++;continue; } if(a[mx] + a[mn] > X){ cnt++; mx--; mn++; }else{ mn++; } } //lbが更新される不等式を書く return cnt < M; } int nibutan(){ int lb=0,ub=N; while(ub-lb>1){ int mid=(lb+ub)/2; if(C(mid)) ub=mid; else lb=mid; //cout<>N>>M; REP(i,0,N) cin>>a[i]; if(N==2) { p(a[1]); return 0; } sort(a+1,a+N); a[N]=-1; int ans = nibutan(); p(ans); return 0; }