// No.638 Sum of "not power of 2"
//
//

#include <iostream>
#include <cmath>
#include <algorithm>
#include <set>
using namespace std;

long long int solve(long long int N);
bool is_valid(long long int a, long long int b, set<long long int> &prohibits);

int main() {
    std::cin.tie(nullptr);
    std::ios::sync_with_stdio(false);

    long long N;
    cin >> N;
    long long ans = solve(N);
    if (ans != -1)
        cout << ans << " " << N - ans << endl;
    else
        cout << ans << endl;
}

long long int solve(long long int N) {
    set<long long> prohibits;
    for (auto i = 0; i < 61; ++i)
        prohibits.insert(pow(2, i));

    long long ans = -1;
    long long a, b;
    for (auto i = 0; i < 61; ++i) {
        long long t = pow(2, i);
        a = t - 1;
        b = N - a;
        if (is_valid(a, b, prohibits)) {
            ans = a;
            break;
        }
        a = t + 1;
        b = N - a;
        if (is_valid(a, b, prohibits)) {
            ans = a;
            break;
        }
    }
    return ans;
}

bool is_valid(long long int a, long long int b, set<long long int> &prohibits) {
    if (a < 1 || b < 1)
        return false;
    if (prohibits.find(a) != prohibits.end())
        return false;
    if (prohibits.find(b) != prohibits.end())
        return false;
    return true;
}