#define _USE_MATH_DEFINES #include "bits/stdc++.h" using namespace std; #define FOR(i,j,k) for(int (i)=(j);(i)<(int)(k);++(i)) #define rep(i,j) FOR(i,0,j) #define each(x,y) for(auto &(x):(y)) #define mp make_pair #define MT make_tuple #define all(x) (x).begin(),(x).end() #define debug(x) cout<<#x<<": "<<(x)< >(b,vector(c,d)) #define vvv(a,b,c,d,e) vector > >(b,vv(a,c,d,e)) using ll = long long; using pii = pair; using vi = vector; using vll = vector; template class ModInt { public: ModInt() :value(0) {} ModInt(long long val) :value((int)(val<0 ? MOD + val%MOD : val%MOD)) { } ModInt& operator+=(ModInt that) { value = value + that.value; if (value >= MOD)value -= MOD; return *this; } ModInt& operator-=(ModInt that) { value -= that.value; if (value<0)value += MOD; return *this; } ModInt& operator*=(ModInt that) { value = (int)((long long)value * that.value % MOD); return *this; } ModInt &operator/=(ModInt that) { return *this *= that.inverse(); } ModInt operator+(ModInt that) const { return ModInt(*this) += that; } ModInt operator-(ModInt that) const { return ModInt(*this) -= that; } ModInt operator*(ModInt that) const { return ModInt(*this) *= that; } ModInt operator/(ModInt that) const { return ModInt(*this) /= that; } ModInt pow(long long k) const { if (value == 0)return 0; ModInt n = *this, res = 1; while (k) { if (k & 1)res *= n; n *= n; k >>= 1; } return res; } ModInt inverse() const { long long a = value, b = MOD, u = 1, v = 0; while (b) { long long t = a / b; a -= t * b; swap(a, b); u -= t * v; swap(u, v); } return ModInt(u); } int toi() const { return value; } private: int value; }; typedef ModInt<1000000007> mint; ostream& operator<<(ostream& os, const mint& x) { os << x.toi(); return os; } int N, E[2001]; mint dp[2001][8][8]; const int A[8] = { 0,1,1,1,0,1,1,0 }; int main() { ios::sync_with_stdio(false); cin.tie(0); cout << fixed << setprecision(20); cin >> N; rep(i, N)cin >> E[i]; rep(i, 8) { if (A[i] == E[0])dp[1][i][i] = 1; } FOR(i, 1, N)rep(j, 8)rep(k, 8) { rep(l, 2) { int nk = (k >> 1) | (l << 2); if (A[nk] == E[i]) { dp[i + 1][j][nk] += dp[i][j][k]; } } } mint ans; rep(j, 8)rep(k, 8) { if ((j>>1&1)==(k>>2&1) && (j&1)==(k>>1&1)) { ans += dp[N][j][k]; } } cout << ans << endl; }