n = gets
a = [20104, 20063, 19892, 20011, 19874, 20199, 19898, 20163, 19956, 19841]
10.times do |i|
a[i] -= n.count("#{i}")
end
b,c = 0,0
a.each_with_index do |i,j|
b = j if i == -1
c = j if i == 1
end
puts "#{b} #{c}"