#include <bits/stdc++.h>
using namespace std;
typedef long long ll;

ll ncr(int n, int r) {
	if (n / 2 < r) {
		r = n - r;
	}
	if (n == r || r == 0) {
		return 1;
	}
	else if (r == 1) {
		return n;
	}
	else {
		return (ncr(n - 1, r - 1) + ncr(n - 1, r))%1000000000;
	}

}

int main() {
	ll n;
	int m, m2;
	cin >> n >> m;
	m2 = n / 1000 % m;

	cout << ncr(m, m2) << endl;



	return 0;
}