#define _USE_MATH_DEFINES #include #include #include #include #include #include #include #include #include #include #include #include #include #include #include using namespace std; //--------------------------------------------------- //ライブラリゾーン!!!! typedef long long ll; typedef long double ld; #define str string #define rep(i,j) for(ll i=0;i<(long long)(j);i++) const ll Mod = 1000000007; const ll gosenchou = 5000000000000000; short gh[2][4] = { { 0,0,-1,1 },{ -1,1,0,0 } }; struct P { ll pos, cost; }; bool operator<(P a, P b) { return a.cost < b.cost; } bool operator>(P a, P b) { return a.cost > b.cost; } struct B {//隣接リスト表現 ll to; ld cost; }; struct E {//辺の情報を入れる変数 ll from, to, cost; }; bool operator<(E a, E b) { return a.cost < b.cost; } struct H { ll x, y; }; bool operator<(H a, H b) { /*if (a.x != b.x) return a.x < b.x; return a.y < b.y;*/ return ((a.x + 1)*(a.y + 1)) < ((b.x + 1)*(b.y + 1)); } bool operator>(H a, H b) { if (a.x != b.x) return a.x > b.x; return a.y > b.y; } bool operator==(H a, H b) { return a.x == b.x&&a.y == b.y; } bool operator!=(H a, H b) { return a.x != b.x || a.y != b.y; } ll gcm(ll i, ll j) {//最大公約数 if (i > j) swap(i, j); if (i == 0) return j; return gcm(j%i, i); } ld rad(H a, H b) { return sqrt(pow(a.x - b.x, 2.0) + pow(a.y - b.y, 2.0)); }//rad=座標上の2点間の距離 ll ari(ll a, ll b, ll c) { return (a + b)*c / 2; }//等差数列の和 ll fact(ll x, ll k, ll p) {//最大値、個数 ll sum = 1; for (int i = 0; i < k; i++) { sum *= (x--); sum %= p; } return sum; }//階乗(正) ll mod_pow(ll x, ll n, ll p) { ll res = 1; while (n > 0) { if (n & 1) res = res*x%p; x = x*x%p; n >>= 1; } return res; }//x^n%p int ctoi(char a) { return (int)a - '0'; } //#define int long long const long long Inf = 4523372036854775807; const int inf = 1500000000; //---------------------------------------------------- //++++++++++++++++++++++++++++++++++++++++++++++++++++ signed main() { string s; cin >> s; int t = 0, r = 0, e = 0; for (int i = 0; i < s.size(); i++) { if (s[i] == 't') t++; if (s[i] == 'r') r++; if (s[i] == 'e') e++; } cout << min(t, min(r, (int)floor(e / 2.0))) << endl; getchar(); getchar(); }