//これは、一様乱数の性質を大いに利用した嘘解法です。(BITを構築したら間に合うのかなあ…) #include #include #include using namespace std; using ll = long long; using ull = unsigned long long; ull seed; int next() { seed = seed ^ (seed << 13); seed = seed ^ (seed >> 7); seed = seed ^ (seed << 17); return (seed >> 33); } int n, q; int a[200000]; int getCnt(int x) { int expect = (long long)x * n / (1LL << 31); int st = max(-1, expect - 1000), ed = min(n, expect + 1000), mid; //oooxxx, [st, ed) while (ed - st >= 2) { mid = (st + ed) / 2; if (a[mid] < x) st = mid; else ed = mid; } return st + 1; } int main() { cin >> n >> q >> seed; for (int i = 0; i < 10000; i++) next(); for (int i = 0; i < n; i++) a[i] = next(); sort(a, a + n); ll sm = 0; for (int i = 0; i < q; i++) { int x = next(); int cnt = getCnt(x); sm ^= ll(cnt) * i; } cout << sm << endl; return 0; }