#include using namespace std; using ll = long long; template using vt = vector; template using vvt = vector>; template using ttt = tuple; using tii = tuple; using vi = vector; #define rep(i,n) for(int i=0;i<(int)(n);i++) #define pb push_back #define mt make_tuple #define ALL(a) (a).begin(),(a).end() #define FST first #define SEC second #define DEB cerr<<"!"<0){if((n&1)==1)r=r*x%m;x=x*x%m;n>>=1;}return r%m;} inline ll lcm(ll d1, ll d2){return d1 / __gcd(d1, d2) * d2;} /* 願はくは花の下にて春死なんそのきさらぎの望月のころ(西行 1118-1190) --This is old Japanese poem expressing the desire to die under tree on the full moon night.(written by Saigyo) In my research, there is possibility that the tree may be seg-tree. */ /*Coding Space*/ // This Segtree written by qcw_pro(my team mate). template // M: monoid, O: operator monoid struct SegTree { using MM = function ; using MO = function ; using OO = function ; using OI = function ; const int n, h; // n: array size, h: height of tree const M m_id; // identity element of monoid const O o_id; // identity element of operator monoid MM mm; MO mo; OO oo; OI oi; vector m; // monoid array vector o; // operator monoid array SegTree(int n, M m_id, O o_id, MM mm, MO mo, OO oo, OI oi = [](const O& a, int b) { return a; }) :n(n), h(sizeof(int)*CHAR_BIT - __builtin_clz(n)), m_id(m_id), o_id(o_id), mm(mm), mo(mo), oo(oo), oi(oi), m(n * 2, m_id), o(n * 2, o_id) {} inline void apply(int i, const O& v, int k) { m[i] = mo(m[i], oi(v, k)); if(i < n) o[i] = oo(o[i], v); } inline void build(int i) { while(i >>= 1) if(o[i] == o_id) m[i] = mm(m[i * 2], m[i * 2 + 1]); } inline void push(int i) { int s{ i >> h ? h : h - 1 }; for(int k{ 1 << (s - 1) }; s > 0; --s, k >>= 1) { int p{ i >> s }; if(o[p] == o_id) continue; apply(p * 2, o[p], k); apply(p * 2 + 1, o[p], k); o[p] = o_id; } } void modify(int l, int r, const O& v) { l += n, r += n; push(l), push(r - 1); int ll{ l }, rr{ r }; for(int k{ 1 }; l < r; l >>= 1, r >>= 1, k <<= 1) { if(l & 1) apply(l++, v, k); if(r & 1) apply(r - 1, v, k); } build(ll), build(rr - 1); } M query(int l, int r) { // [l,r) l += n, r += n; push(l), push(r - 1); M a{ m_id }, b{ m_id }; for(; l < r; l >>= 1, r >>= 1) { if(l & 1) a = mm(a, m[l++]); if(r & 1) b = mm(m[r - 1], b); } return mm(a, b); } }; //SegTree (size, M_I, O_I, MM, MO, OO) int F (int a, int b){return max(a, b);}; SegTree st(100005, 0, 0, F, F,F); int main(){ int n; cin >> n; map> in; rep(i,n){ int ii; cin >> ii; in[ii].pb(i); } for(auto&& i:in){ int a; int b; if(i.SEC.size() == 0) continue; a = i.SEC[0]; b = *(--(i.SEC.end())); st.modify(a,b+1,i.FST); cerr << a <<" "<< b <<" "<< i.FST << endl; } rep(i,n) cout << st.query(i,i+1) << (i == n-1?"\n":" "); }