#include "bits/stdc++.h" using namespace std; typedef long long ll; typedef pair pii; typedef pair pll; const int INF = 1e9; const ll LINF = 1e18; template ostream& operator << (ostream& out,const pair& o){ out << "(" << o.first << "," << o.second << ")"; return out; } template ostream& operator << (ostream& out,const vector V){ for(int i = 0; i < V.size(); i++){ out << V[i]; if(i!=V.size()-1) out << " ";} return out; } template ostream& operator << (ostream& out,const vector > Mat){ for(int i = 0; i < Mat.size(); i++) { if(i != 0) out << endl; out << Mat[i];} return out; } template ostream& operator << (ostream& out,const map mp){ out << "{ "; for(auto it = mp.begin(); it != mp.end(); it++){ out << it->first << ":" << it->second; if(mp.size()-1 != distance(mp.begin(),it)) out << ", "; } out << " }"; return out; } /* 問題文============================================================ ================================================================= 解説============================================================= ================================================================ */ ll MOD =0; // a^b % MOD; ll powmod(ll a,ll b) {ll res=1;a%=MOD; for(;b;b>>=1){if(b&1)res=res*a%MOD;a=a*a%MOD;}return res;} // 逆元 1/a % MOD ll inversemod(ll a) { return powmod(a,MOD - 2);} bool IsPrime(ll num) { if (num < 2) return false; else if (num == 2) return true; else if (num % 2 == 0) return false; // 偶数はあらかじめ除く double sqrtNum = sqrt(num); for (int i = 3; i <= sqrtNum; i += 2){ if (num % i == 0){ return false; } } return true; } ll solve(ll N,ll M){ ll res = 0; if(N == 0) return res; MOD = M; if(N >= M) return res; if(M <= 200000){ res = 1; while(N) (res *= N--)%=M; return res; } if(IsPrime(M)){ res = M-1; for(ll X = N+1; X < M;X++){ res = (res * inversemod(X))%MOD; } } return res; } int main(void) { cin.tie(0); ios_base::sync_with_stdio(false); ll T; cin >> T; while(T--){ ll N,M; cin >> N >> M; cout << T << " " << solve(N,M) << endl; } return 0; }