#include typedef long long ll; using namespace std; int INF = 1LL << 30; int MOD = 1e9+7; main(){ ll N; cin >> N; ll i; for(i = sqrt(N*2);i * (i+1) < N*2;i++){} if(i * (i+1) / 2 == N){ cout << "YES" << endl; cout << i << endl; }else{ cout << "NO" << endl; } }