#include <iostream>
#include <vector>
#include <string>
#include <stack>
#include <queue>
#include <deque>
#include <set>
#include <map>
#include <algorithm>	// require sort next_permutation count __gcd reverse etc.
#include <cstdlib>	// require abs exit atof atoi 
#include <cstdio>		// require scanf printf
#include <functional>
#include <numeric>	// require accumulate
#include <cmath>		// require fabs
#include <climits>
#include <limits>
#include <cfloat>
#include <iomanip>	// require setw
#include <sstream>	// require stringstream 
#include <cstring>	// require memset
#include <cctype>		// require tolower, toupper
#include <fstream>	// require freopen
#include <ctime>		// require srand
#define rep(i,n) for(int i=0;i<(n);i++)
#define ALL(A) A.begin(), A.end()
#define each(i,c) for(auto i=(c).begin();i!=(c).end();++i)
#define exist(s,e) ((s).find(e)!=(s).end())
#define clr(a) memset((a),0,sizeof(a))
#define nclr(a) memset((a),-1,sizoef(a))
#define sz(s) (int)((s).size())
#define INRANGE(x,s,e) ((s)<=(x) && (x)<(e))
#define pb push_back
#define MP(x,y) make_pair((x),(y))

using namespace std;

typedef long long ll;
typedef pair<int, int> P;

const int ans[10][10] = {
		{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },	// 0
		{ 1, 1, 1, 1, 1, 1, 1, 1, 1, 1 },	// 1
		{ 6, 2, 4, 8, 6, 2, 4, 8, 6, 2 },	// 2
		{ 1, 3, 9, 7, 1, 3, 9, 7, 1, 3 },	// 3
		{ 6, 4, 6, 4, 6, 4, 6, 4, 6, 4 },	// 4
		{ 5, 5, 5, 5, 5, 5, 5, 5, 5, 5 },	// 5
		{ 6, 6, 6, 6, 6, 6, 6, 6, 6, 6 },	// 6
		{ 1, 7, 9, 3, 1, 7, 9, 3, 1, 7 },	// 7
		{ 6, 8, 4, 2, 6, 8, 4, 2, 6, 8 },	// 8
		{ 1, 9, 1, 9, 1, 9, 1, 9, 1, 9 }	// 9
};

int main()
{
	ios_base::sync_with_stdio(0);
	string N, M; cin >> N >> M;
	
	int n = (int)(N[N.length()-1] - '0' );
	int m = (int)(M[M.length()-1] - '0' );
	if (M.length() >= 2 ){
		m += (int)(M[M.length()-2] - '0' )*10;
	} // end if

	int res = 0;
	switch (n ){
		case 0:
		case 1:
			res = ans[n][0]; break;
		case 2:
		case 8:
			if (m == 0 )
				res = 1;
			else
				res = ans[n][m%4];
			break;
		case 3:
		case 7:
			res = ans[n][m%4]; break;
		case 4:
			if (m == 0 )
				res = 1;
			else
				res = ans[n][m%2]; break;
		case 5:
		case 6:
			if (m == 0 ) res = 1;
			else res = ans[n][0]; break;
		case 9:
			res = ans[n][m%2]; break;
	} // end switch

	cout << res << endl;

	return 0;
}