#include #define REP(i, n) for (int i = 0; i < (n); i++) #define FOR(i, init, n) for(int i = init; i < (n); i++) #define ALL(obj) (obj).begin(), (obj).end() #define RALL(obj) (obj).rbegin(), (obj).rend() #define Cout(obj) cout << obj << endl #define Size(obj) (obj).size() #define fcout cout << fixed << setprecision(10) #define fi first #define se second using namespace std; using ll = long long int; using P = pair; using T = tuple; using edge = struct { int to, cost; }; const int MOD = 1e9 + 7; const int iINF = 1e9; const long long int llINF = 1e18; const double PI = acos(-1.0); const int dx[4] = {1, 0, -1, 0}; const int dy[4] = {0, 1, 0, -1}; int main() { cin.tie(0); ios::sync_with_stdio(false); int N; cin >> N; vector A(N), B(N); REP(i, N) { cin >> A[i] >> B[i]; } int n = N / 2, half = N - n; vector candi; REP(S, 1 << n) { ll sumA = 0, sumB = 0; REP(i, n) { if((S >> i) & 1) { sumA += A[i]; } else { sumB += B[i]; } } candi.push_back(sumA - sumB); } ll ans = llINF; sort(ALL(candi)); REP(S, 1 << half) { ll sumA = 0, sumB = 0; REP(i, half) { if((S >> i) & 1) { sumA += A[i + n]; } else { sumB += B[i + n]; } } auto itr = lower_bound(ALL(candi), -(sumA - sumB)); if(itr != candi.begin()) { auto itr2 = itr; itr2--; ans = min(ans, abs(sumA - sumB + *itr2)); } if(itr != candi.end()) { ans = min(ans, abs(sumA - sumB + *itr)); itr++; if(itr != candi.end()) { ans = min(ans, abs(sumA - sumB + *itr)); } } } Cout(ans); return 0; }