#include #define rep(i, n) for (int i = 0; i < (n); i++) #define fr(i, a, b) for (int i = (a); i < (b); i++) #define all(c) (c).begin(), (c).end() using namespace std; typedef long long ll; const ll inf = 1e9; const ll mod = 1e9 + 7; int N; const int maxn = 100; ll A[maxn]; ll dp[maxn][maxn]; // last a[i], last last a[i]; ll xdp[maxn]; ll dp2[maxn][maxn]; ll ydp[maxn]; void solve() { rep (i, maxn) rep (j, maxn) dp[i][j] = 0; rep (i, N) { rep (j, i) { if (A[j] < A[i]) dp[i][j] = 1; else dp[i][j] = 0; rep (k, j) { if ((A[j] < A[i] && A[k] < A[j]) && abs(A[k] - A[j]) < abs(A[j] - A[i])) { if (dp[i][j] < dp[j][k] + 1) { dp[i][j] = dp[j][k] + 1; } } } } } rep (i, N) { xdp[i] = 0; rep (j, N) { xdp[i] = max(xdp[i], dp[i][j]); } } } int main() { int T; cin >> T; rep (k, T) { cin >> N; rep (i, N) { cin >> A[i]; } solve(); rep (i, N) { ydp[i] = xdp[i]; } reverse(A, A + N); solve(); reverse(xdp, xdp + N); ll ans = 0; rep (i, N) { ans = max(ans, xdp[i] + ydp[i] + 1); } cout << ans << endl; } }