# include <iostream>
# include <algorithm>
#include <array>
# include <cassert>
#include <cctype>
#include <climits>
#include <numeric>
# include <vector>
# include <string>
# include <set>
# include <map>
# include <cmath>
# include <iomanip>
# include <functional>
# include <tuple>
# include <utility>
# include <stack>
# include <queue>
# include <list>
# include <bitset>
# include <complex>
# include <chrono>
# include <random>
# include <limits.h>
# include <unordered_map>
# include <unordered_set>
# include <deque>
# include <cstdio>
# include <cstring>
#include <stdio.h>
#include <stdlib.h>
#include <cstdint>
#include <cfenv>
//#include <bits/stdc++.h>
using namespace std;
using LL = long long;
using ULL = unsigned long long;
long long MOD = 1000000000 + 7;
constexpr long long INF = std::numeric_limits<LL>::max();
const double PI = acos(-1);
#define fir first
#define sec second
#define thi third
#define debug(x) cerr<<#x<<": "<<x<<'\n'
typedef pair<LL, LL> Pll;
typedef pair<LL, pair<LL, LL>> Ppll;
typedef pair<LL, pair<LL, bitset<100001>>> Pbll;
typedef pair<LL, pair<LL, vector<LL>>> Pvll;
typedef pair<LL, LL> Vec2;
struct Tll { LL first, second, third; };
typedef pair<LL, Tll> Ptll;
#define rep(i,rept) for(LL i=0;i<rept;i++)
#define Mfor(i,mf) for(LL i=mf-1;i>=0;i--)
LL h, w, n, m, k, t, s, q, last, cnt, sum[2000000], ans, dp[200000][200];
Pll a[2000000],b[2000000];
string str,ss;
bool f;
char c;
int di[4][2] = { { 0,1 },{ 1,0 },{ -1,0 } ,{ 0,-1 } };
struct Edge { LL to, cost; };
vector<Edge>vec[1000000];
vector<Pll>v;
map<string, LL>ma;
set<LL>st;
void YN(bool f) {
	if (f)
		cout << "YES" << endl;
	else
		cout << "NO" << endl;
}
void yn(bool f) {
	if (f)
		cout << "Yes" << endl;
	else
		cout << "No" << endl;
}
LL partf(LL n, LL k) {
	if (k == 0 && n == 0)return 1;
	if (k <= 0 || n < 0)return 0;
	//dp=-1で初期化
	if (dp[n][k] != -1)return dp[n][k];
	dp[n][k] = partf(n - s * (k - 1), k - 1) + partf(n - k, k);
	dp[n][k] %= MOD;
	return dp[n][k];
}
int main() {
	cin >> n >> m >> s;
	rep(i,m+1)
		rep(j, n+1) {
		dp[i][j] = -1;
	}
	cout << partf(m,n) << endl;
	return 0;
}