#include #include #include #include #include #include #include #include #include #include #include #include #include #include #define rep(x, to) for (int x = 0; x < (to); x++) #define REP(x, a, to) for (int x = (a); x < (to); x++) #define foreach(itr, x) for (typeof((x).begin()) itr = (x).begin(); itr != (x).end(); itr++) using namespace std; typedef long long ll; typedef pair PII; typedef pair PLL; int N, T; int a[105]; int dp[105][105]; int dp2[105][105]; int dfs(int i, int j, int tdp[105][105]) { if (tdp[i][j] != 0) return tdp[i][j]; int res = 1; int k_not_exist = 1; for (int k = 0; k < j; k++) { if (a[j] < a[i] && a[k] < a[j] && a[i]-a[j] > a[j]-a[k]) { res = max(res, 1 + dfs(j, k, tdp)); k_not_exist = 0; } } res += k_not_exist; return tdp[i][j] = res; } int main() { cin >> T; while (T--) { int ans = 1; memset(dp, 0, sizeof(dp)); memset(dp2, 0, sizeof(dp2)); cin >> N; rep(i, N) cin >> a[i]; //up for (int i = 0; i < N; i++) { for (int j = 0; j < i; j++) { if (a[j] < a[i]) { dfs(i, j, dp); } } } //down reverse(a, a+N); for (int i = 0; i < N; i++) { for (int j = 0; j < i; j++) { if (a[j] < a[i]) dfs(i, j, dp2); } } #if 0 rep(i, 5) rep(j, 5) { printf("%d%c", dp[i][j], j == 5 - 1 ? '\n' : ' '); } #endif for (int i = 0; i < N; i++) { for (int j = 0; j <= i; j++) { for (int k = 0; k < N-i-1; k++) { if (dp[i][j] + dp2[N-i-1][k] - (dp[i][j]>0&&dp2[N-i-1][k]>0) > ans) { //頂上のカウント重複のため-1 ans = dp[i][j] + dp2[N-i-1][k]-(dp[i][j]>0&&dp2[N-i-1][k]>0); //printf("dp[%d][%d]+dp2[%d][%d]=%d+%d=%d\n", i,j,N-i-1,k,dp[i][j],dp2[N-i-1][k],dp[i][j]+dp2[N-i-1][k]); } } } } cout << ans << endl; } return 0; }