#include<iostream>
using ll = long long;
using namespace std;
int main(){
    ll a[101010]={},b[101010]={},n,x,ans=0;
    cin >> n >> x;
    for(ll i=0;i<n;i++){
            cin >> a[i];
            b[a[i]]++;
    }
    for(ll i=0;i<n;i++){
        ll f = x-a[i];
        if(f<=100000&&f>=0)  ans+=b[f];
    }
    cout << ans << endl;
    return 0;
}