#include "bits/stdc++.h" using namespace std; typedef long long ll; typedef pair pii; typedef pair pll; const int INF = 1e9; const ll LINF = 1e18; template ostream& operator << (ostream& out,const pair& o){ out << "(" << o.first << "," << o.second << ")"; return out; } template ostream& operator << (ostream& out,const vector V){ for(int i = 0; i < V.size(); i++){ out << V[i]; if(i!=V.size()-1) out << " ";} return out; } template ostream& operator << (ostream& out,const vector > Mat){ for(int i = 0; i < Mat.size(); i++) { if(i != 0) out << endl; out << Mat[i];} return out; } template ostream& operator << (ostream& out,const map mp){ out << "{ "; for(auto it = mp.begin(); it != mp.end(); it++){ out << it->first << ":" << it->second; if(mp.size()-1 != distance(mp.begin(),it)) out << ", "; } out << " }"; return out; } /* 問題文============================================================ ================================================================= 解説============================================================= ================================================================ */ typedef long double ld; ld solve(){ ld res = 0; ll N; cin >> N; ld p[3]; for(int i = 0; i < 3;i++) cin >> p[i]; vector> q(N,vector(3)); for(auto& vec:q) for(auto& in:vec) cin >> in; for(int i = 0; i < N;i++){ for(int j = i+1; j < N;j++){ for(int k = j+1; k < N;k++){ vector ab(3),ac(3); for(int l = 0; l < 3;l++){ ab[l] = q[j][l] - q[i][l]; ac[l] = q[k][l] - q[i][l]; } ld a = ab[1]*ac[2]-ab[2]*ac[1]; ld b = ab[2]*ac[0]-ab[0]*ac[2]; ld c = ab[0]*ac[1]-ab[1]*ac[0]; ld d = -(a*q[i][0]+b*q[i][1]+c*q[i][2]); // 平面方程式 ax+by+cz+d=0 res += abs(a*p[0]+b*p[1]+c*p[2]+d)/sqrt(a*a+b*b+c*c); } } } return res; } int main(void) { cin.tie(0); ios_base::sync_with_stdio(false); cout << fixed << setprecision(12) << solve() << endl; return 0; }