#include #include #include #include #include #include #include #include #include #include #define MAX_N 100001 #define INF_INT 2147483647 #define INF_LL 9223372036854775807 #define REP(i,n) for(int i=0;i<(int)(n);i++) using namespace std; typedef long long int ll; typedef pair P; void init(int n); int find(int n); void unite(int x,int y); bool same(int x, int y); ll bpow(ll,ll,ll); typedef vector vec; typedef vector mat; mat mul(mat &A,mat &B); mat pow(mat A,ll n); int dx[4] = {1,0,0,-1}; int dy[4] = {0,1,-1,0}; bool cmp_P(const P &a,const P &b){ return a.second < b.second; } int main() { int N,I,res=1,dp[1000001]; fill(dp,dp+1000001,-INF_INT); cin >> N; vector x(N,0); set sets; REP(i,N){ cin >> x[i]; sets.insert(x[i]); } sort(x.begin(),x.end()); REP(i,N){ dp[x[i]] = 0; vector d(0); I = sqrt(x[i]); for(int j=1;j<=I;j++){ if(!(x[i] % j)){ if(sets.count(j)){ d.push_back(j); } if(sets.count(x[i]/j)) d.push_back(x[i]/j); } } sort(d.begin(),d.end()); int s; for(int j=0;j>= 1; } return res; } const int MOD = 1000000007; mat mul(mat &A, mat &B){ mat C(A.size(),vec(B[0].size())); REP(i,A.size())REP(k,B.size())REP(j,B[0].size()){ C[i][j] = (C[i][j] + A[i][k] * B[k][j]) % MOD; } return C; } mat pow(mat A,ll n) { mat B(A.size(),vec(A.size())); REP(i,A.size()){ B[i][i] = 1; } while(n > 0){ if ( n & 1) B = mul(B,A); A = mul(A,A); n >>= 1; } return B; }