#include using namespace std; using VS = vector; using LL = long long; using VI = vector; using VVI = vector; using PII = pair; using PLL = pair; using VL = vector; using VVL = vector; #define ALL(a) begin((a)),end((a)) #define RALL(a) (a).rbegin(), (a).rend() #define SZ(a) int((a).size()) #define SORT(c) sort(ALL((c))) #define RSORT(c) sort(RALL((c))) #define UNIQ(c) (c).erase(unique(ALL((c))), end((c))) #define FOR(i, s, e) for (int(i) = (s); (i) < (e); (i)++) #define FORR(i, s, e) for (int(i) = (s); (i) > (e); (i)--) #define debug(x) cerr << #x << ": " << x << endl const int INF = 1e9; const LL LINF = 1e16; const LL MOD = 1000000007; const double PI = acos(-1.0); int DX[8] = { 0, 0, 1, -1, 1, 1, -1, -1 }; int DY[8] = { 1, -1, 0, 0, 1, -1, 1, -1 }; /* ----- 2018/08/26 Problem: yukicoder 251 / Link: http://yukicoder.me/problems/no/251 ----- */ /* ------問題------ 入力に整数 N と M が与えられる。 NのM乗(NM) を 129402307で割った余りを出力せよ。(129402307は素数である) -----問題ここまで----- */ /* -----解説等----- ----解説ここまで---- */ const int mod = 129402307; long long modpow(long long a, long long b) { if (b == 0) return 1; return modpow(a * a % mod, b / 2) * (b & 1 ? a : 1) % mod; } int main() { cin.tie(0); ios_base::sync_with_stdio(false); string N, M; cin >> N >> M; LL n = 0; for (char c : N) { n *= 10; n += c - '0'; n %= mod; } LL m = 0; for (char c : M) { m *= 10; m += c - '0'; m %= (mod-1); } LL ans = modpow(n, m); cout << ans << "\n"; return 0; }