#include #define MAX_N 100001 #define INF_INT 2147483647 #define INF_LL 9223372036854775807 #define REP(i,n) for(int i=0;i<(int)(n);i++) using namespace std; typedef long long int ll; typedef pair P; void init(int n); int find(int n); void unite(int x,int y); bool same(int x, int y); ll bpow(ll,ll,ll); typedef vector vec; typedef vector mat; mat mul(mat &A,mat &B); mat pow(mat A,ll n); int dx[4] = {1,0,0,-1}; int dy[4] = {0,1,-1,0}; bool cmp_P(const P &a,const P &b){ return a.second < b.second; } int main() { ll N,tmp=0; string S[52]; cin >> N; vector vec(N,0); REP(i,N) cin >> S[i]; REP(i,N){ tmp = 0; if(S[i][0] == 'D')tmp+=100; if(S[i][0] == 'C')tmp+=200; if(S[i][0] == 'H')tmp+=300; if(S[i][0] == 'S')tmp+=400; if(S[i][1] == 'A')tmp+=1; if(S[i][1] == 'T')tmp+=10; if(S[i][1] == 'J')tmp+=11; if(S[i][1] == 'Q')tmp+=12; if(S[i][1] == 'K')tmp+=13; if(S[i][1] <= '9' && S[i][1] >= '0')tmp+=S[i][1]-'0'; vec[i] = tmp; } sort(vec.begin(),vec.end()); REP(i,vec.size()){ string T = ""; switch(vec[i]/100){ case 1: T += "D"; break; case 2: T += "C"; break; case 3: T += "H"; break; case 4: T += "S"; break; } switch(vec[i]%100){ case 1: T += "A"; break; case 10: T += "T"; break; case 11: T += "J"; break; case 12: T += "Q"; break; case 13: T += "K"; break; default: char d = '0'+ vec[i]%100; T += d; break; } cout << T << " "; } cout << endl; return 0; } int par[MAX_N]; int ranks[MAX_N]; //n要素で初期化 void init(int n){ REP(i,n){ par[i] = i; ranks[i] = 0; } } //木の根を求める int find(int x){ if(par[x] == x){ return x; }else{ return par[x] = find(par[x]); } } void unite(int x,int y){ x = find(x); y = find(y); if(x == y) return ; if(ranks[x] < ranks[y]){ par[x] = y; }else{ par[y] = x; if(ranks[x] == ranks[y]) ranks[x]++; } } bool same(int x, int y){ return find(x) == find(y); } ll bpow(ll a, ll n,ll mod){ int i = 0; ll res=1; while(n){ if(n & 1) res = (res*a) % mod; a = (a*a) % mod; n >>= 1; } return res; } const int MOD = 1000000007; mat mul(mat &A, mat &B){ mat C(A.size(),vec(B[0].size())); REP(i,A.size())REP(k,B.size())REP(j,B[0].size()){ C[i][j] = (C[i][j] + A[i][k] * B[k][j]) % MOD; } return C; } mat pow(mat A,ll n) { mat B(A.size(),vec(A.size())); REP(i,A.size()){ B[i][i] = 1; } while(n > 0){ if ( n & 1) B = mul(B,A); A = mul(A,A); n >>= 1; } return B; }