#include <bits/stdc++.h>

using namespace std;
#define pb push_back
#define mp make_pair
#define all(x) (x).begin(),(x).end()
#define rep(i,n) for(int i=0;i<(n);i++)
constexpr int MOD = 1000000007;
typedef long long ll;
typedef unsigned long long ull;
typedef pair<int,int> pii;
constexpr int dx[] = {1, 0, -1, 0, 1, 1, -1, -1};
constexpr int dy[] = {0, -1, 0, 1, 1, -1, -1, 1};

template <typename T> ostream &operator<<(ostream &os, const vector<T> &vec){os << "["; for (const auto &v : vec) {os << v << ","; } os << "]"; return os; }
template <typename T, typename U> ostream &operator<<(ostream &os, const pair<T, U> &p){os << "(" << p.first << ", " << p.second << ")"; return os;}

struct Phone {
  int h, w, t;
  bool operator<(const Phone &rhs) const {
    if (h == rhs.h) {
      return w > rhs.w;
    }
    return h < rhs.h;
  }
};

struct BIT {
  vector<ll> data;
  BIT(int n): data(n + 1) {}
  ll getmax(int a) {
    ll ret = 0;
    for(int i = a; i > 0; i -= i & -i) {
      ret = max(ret, data[i]);
    }
    return ret;
  }
  void update(int a, ll w) {
    for(int i = a; i < data.size(); i += i & -i) {
      data[i] = max(data[i], w);
    }
  }
};

// BIT解（想定解）
ll solve1(int N, vector<Phone> &P) {
  sort(all(P));
  vector<int> W(N);
  for (int i = 0; i < N; i++) {
    W[i] = P[i].w;    
  }
  sort(all(W));
  W.erase(unique(W.begin(), W.end()), W.end());

  BIT bit(N + 2);
  for(int i = 0; i < N; i++) {
    int k = lower_bound(all(W), P[i].w) - W.begin() - 1;
    k += 2; // for BIT
    ll mi = bit.getmax(k);
    bit.update(k + 1, mi + P[i].t);
  }
  return bit.getmax(N + 2);
}

// Naive DP解(O(N^2), TLE)
ll solve2(int N, vector<Phone> &P) {
  sort(all(P));
  vector<ll> dp(N, 0);
  for(int i = 0; i < N; i++) {
    ll ma = 0;
    for(int j = 0; j < i; j++) {
      if (P[j].w >= P[i].w) continue;
      ma = max(ma, dp[j]);
    }
    dp[i] = ma + P[i].t;
  }
  return *max_element(all(dp));
}

void solve() {
  int N;
  cin >> N;
  if (N < 1 || N > 200000) exit(1);
  map<pii, int> M;
  for(int i = 0; i < N; i++) {
    int h, w, t;
    cin >> h >> w >> t;
    if (h < 1 || h > 1000000000) exit(1);
    if (w < 1 || w > 1000000000) exit(1);
    if (t < 1 || t > 1000000000) exit(1);
    M[{h, w}] = max(M[{h, w}], t);
  }
  vector<Phone> P;
  for(auto &&x : M) {
    P.push_back({x.first.first, x.first.second, x.second});
  }
  N = P.size();

  if (N > 2000) {
    cout << solve1(N, P) << endl;
  } else {
    ll ans1 = solve1(N, P);
    ll ans2 = solve2(N, P);
    if (ans1 != ans2) {
      cout << "Error: " << ans1 << " : " << ans2 << endl;
    } else {
      cout << ans1 << endl;
    }
  }
}

int main() {
  std::cin.tie(0);
  std::ios::sync_with_stdio(false);
  cout.setf(ios::fixed);
  cout.precision(16);
  solve();
  return 0;
}