#include <algorithm>
#include <iostream>
#include <numeric>
#include <queue>
#include <vector>

#define rep(i, n) for (int i = 0; i < (int)(n); i++)
using namespace std;

struct UnionFind {
  vector<int> par;
  vector<int> rank;
  UnionFind(int n) {
    par.resize(n);
    rep(i, n) par[i] = i;
    rank.resize(n, 0);
  }
  int find(int i) {
    if (i == par[i])
      return par[i];
    else
      return par[i] = find(par[i]);
  }
  void unite(int i, int j) {
    i = find(i), j = find(j);
    if (i == j) return;
    if (rank[i] < rank[j]) {
      par[i] = j;
    } else {
      par[j] = i;
      if (rank[i] == rank[j]) rank[i]++;
    }
  }
};

int main() {

  int n, m, k;
  cin >> n >> m >> k;

  struct Edge {
    int a, b, c;
  };
  vector<Edge> edges;
  rep(_, m) {
    int a, b, c;
    cin >> a >> b >> c;
    edges.push_back(Edge{a - 1, b - 1, c});
  }
  long long sum = 0;
  UnionFind uf(n);
  vector<int> special(m, false);
  rep(_, k) {
    int i;
    cin >> i;
    uf.unite(edges[i - 1].a, edges[i - 1].b);
    sum += (long long)edges[i - 1].c;
    special[i] = true;
  }
  struct E {
    int to, c;
    bool operator<(const E &r) const { return c > r.c; }
  };
  vector<vector<E>> g(n);
  rep(i, m) {
    auto a = uf.find(edges[i].a), b = uf.find(edges[i].b);
    if (a != b) {
      g[a].push_back(E{b, edges[i].c});
      g[b].push_back(E{a, edges[i].c});
    }
  }

  auto prim = [&](vector<vector<E>> &g) {
    vector<int> visited(n, false);
    priority_queue<E> q;
    auto s = uf.find(0);
    visited[s] = true;
    for (auto e : g[s]) {
      q.push(e);
    }
    long long ret = 0;
    while (q.size() > 0) {
      auto e = q.top();
      q.pop();
      if (visited[e.to]) continue;
      visited[e.to] = true;
      ret += (long long)e.c;
      for (auto ne : g[e.to]) {
        if (!visited[ne.to]) { q.push(ne); }
      }
    }
    return ret;
  };

  sum += prim(g);
  auto tot = accumulate(
      edges.begin(), edges.end(), 0LL,
      [&](long long res, const auto &e) { return res + (long long)e.c; });

  cout << tot - sum << endl;

  return 0;
}