#include #include using namespace std; #define ll long long #define rep(i,n) for(int (i)=0;(i)<(n);(i)++) int digit(char c) { return static_cast(c-'0'); } int digitsum(string s) { int sum=0; for(auto& ch : s)sum+=digit(ch); return sum; } int main() { cin.tie(0); ios::sync_with_stdio(false); cout<::max_digits10); string n,k; cin>>n>>k; string temp = "x285714"; // cout << digitsum(n) << " " << digit(k[0]) << endl; if(digit(n.back())%2==0) { // n^k = 0 mod 2 if(digitsum(n)%3==0) { // n^k = 0 mod3 => n^k=0 mod6 cout << temp[6] << endl; } if(digitsum(n)%3==1) { // n^k=1 mod 3 => n^k = 4 mod6 cout << temp[4] << endl; } if(digitsum(n)%3==2&&digit(k.back())%2==1) { // n^k = 2 mod3 => n^k=2 mod6 cout << temp[2] << endl; } if(digitsum(n)%3==2&&digit(k.back())%2==0) // n^k == 1 mod3 => n^k == 4 mod 6 cout << temp[4] << endl; } else { // n^k=1 mod 2 if(digitsum(n)%3==0) { // n^k=0mod3 => n^k=3mod6 cout << temp[3] << endl; } if(digitsum(n)%3==1) { // n^k=1mod3 => n^k=1mod6 cout << temp[1] << endl; } if(digitsum(n)%3==2&&digit(k.back())%2==1) { // n^k=2mod3 => n^k=5mod6 cout << temp[5] << endl; } if(digitsum(n)%3==2&&digit(k.back())%2==0) // n^k==1mod3 => n^k=1 mod6 cout << temp[1] << endl; } return 0; }