#include <iostream>
using namespace std;

long n;
bool ok(long k) {
	return k * (k + 1) >= 2 * n;
}

int main() {
	cin >> n;
	
	long lo = 0;
	long hi = 2000000000;
	while (hi - lo > 1) {
		long mid = (lo + hi) / 2;
		if (ok(mid)) {
			hi = mid;
		} else {
			lo = mid;
		}
	}
	
	if (hi * (hi + 1) == n * 2) {
		cout << "YES" << endl;
		cout << hi << endl;
	} else {
		cout << "NO" << endl;
	}
}