#include using namespace std; using ll = long long; ll sum1[100000], sum2[100000]; ll solve(int L, int R, int p, int sz) { if (L > p) { return (ll)p * (R - L + 1); } if (R <= sz) { return sum1[R] - sum1[L - 1]; } ll res = 0; if (R > p) { res += (ll)p * (R - p); R = p; } if (L <= sz) { res += sum1[sz] - sum1[L - 1]; L = sz + 1; } // L > sz && R <= p int bL = p / L; int bR = p / R; // bL >= bR if (bL == bR) { res += (ll)(p % L + p % R) * (R - L + 1) / 2; return res; } int hoge = p / bL; res += (ll)(p % L + p % hoge) * (hoge - L + 1) / 2; int foo = p / bR; res += sum2[bR] - sum2[bR - 1] - (ll)(p % R + p % foo) * (foo - R + 1) / 2 + p % R; bL--; bR++; if (bL < bR) return res; // bL >= bR res += sum2[bL] - sum2[bR - 1]; return res; } int main() { cin.tie(0); ios::sync_with_stdio(false); int p; int q; cin >> p >> q; int sz = 1; while (sz * sz < p) { int nsz = sz + 1; if (nsz * nsz > p) break; sz = nsz; } for (int i = 2; i <= sz; i++) { sum1[i] = p % i; } for (int i = 1; i <= sz; i++) { sum1[i] += sum1[i - 1]; } for (int i = 1; i <= sz; i++) { int last = p / i; int first = p / (i + 1) + 1; int minv = p % last; int maxv = p % first; sum2[i] = (ll)(maxv + minv) * (last - first + 1) / 2; } for (int i = 1; i <= sz; i++) { sum2[i] += sum2[i - 1]; } for (int i = 0; i < q; i++) { int L, R; cin >> L >> R; cout << solve(L, R, p, sz) << endl; } return 0; }