#include <iostream>
#include <math.h>

int main()
{
    unsigned long long n;
    std::cin >> n;
    
    unsigned long long m = n * 2;
    m = (int)sqrt(m);
    
    if(((m * (m + 1)) / 2) == n)
    {
        std::cout << "YES\n" << m << std::endl;
    }
    else
    {
        std::cout << "NO" << std::endl;
    }
    
    return 0;
}